GIN搜索的O(n2)负载度
GIN索引如果使用很长的关键词列表进行搜索，会导致性能显著下降。本文解释了为什么GIN索引关键词搜索的时间复杂度为O(n^2)
GIN索引如果使用很长的关键词列表进行搜索，会导致性能显著下降。本文解释了为什么GIN索引关键词搜索的时间复杂度为O(n^2)
Here is the detail of why that query have O(N^2) inside GIN implementation.
Details
Inspect the index example_keys_idx
postgres=# select oid,* from pg_class where relname = 'example_keys_idx';
-[ RECORD 1 ]-------+-----------------
oid | 20699
relname | example_keys_idx
relnamespace | 20692
reltype | 0
reloftype | 0
relowner | 10
relam | 2742
relfilenode | 20699
reltablespace | 0
relpages | 2051
reltuples | 300000
relallvisible | 0
reltoastrelid | 0
relhasindex | f
relisshared | f
relpersistence | p
relkind | i
relnatts | 1
relchecks | 0
relhasoids | f
relhasrules | f
relhastriggers | f
relhassubclass | f
relrowsecurity | f
relforcerowsecurity | f
relispopulated | t
relreplident | n
relispartition | f
relrewrite | 0
relfrozenxid | 0
relminmxid | 0
relacl |
reloptions | {fastupdate=off}
relpartbound |
Find index information via index’s oid
postgres=# select * from pg_index where indexrelid = 20699;
-[ RECORD 1 ]--+------
indexrelid | 20699
indrelid | 20693
indnatts | 1
indnkeyatts | 1
indisunique | f
indisprimary | f
indisexclusion | f
indimmediate | t
indisclustered | f
indisvalid | t
indcheckxmin | f
indisready | t
indislive | t
indisreplident | f
indkey | 2
indcollation | 0
indclass | 10075
indoption | 0
indexprs |
indpred |
Find corresponding operator class for that index via indclass
postgres=# select * from pg_opclass where oid = 10075;
-[ RECORD 1 ]+----------
opcmethod | 2742
opcname | array_ops
opcnamespace | 11
opcowner | 10
opcfamily | 2745
opcintype | 2277
opcdefault | t
opckeytype | 2283
Find four operator corresponding to operator faimily array_ops
postgres=# select * from pg_amop where amopfamily =2745;
-[ RECORD 1 ]--+-----
amopfamily | 2745
amoplefttype | 2277
amoprighttype | 2277
amopstrategy | 1
amoppurpose | s
amopopr | 2750
amopmethod | 2742
amopsortfamily | 0
-[ RECORD 2 ]--+-----
amopfamily | 2745
amoplefttype | 2277
amoprighttype | 2277
amopstrategy | 2
amoppurpose | s
amopopr | 2751
amopmethod | 2742
amopsortfamily | 0
-[ RECORD 3 ]--+-----
amopfamily | 2745
amoplefttype | 2277
amoprighttype | 2277
amopstrategy | 3
amoppurpose | s
amopopr | 2752
amopmethod | 2742
amopsortfamily | 0
-[ RECORD 4 ]--+-----
amopfamily | 2745
amoplefttype | 2277
amoprighttype | 2277
amopstrategy | 4
amoppurpose | s
amopopr | 1070
amopmethod | 2742
amopsortfamily | 0
https://www.postgresql.org/docs/10/xindex.html
Table 37.6. GIN Array Strategies
| Operation | Strategy Number |
|---|---|
| overlap | 1 |
| contains | 2 |
| is contained by | 3 |
| equal | 4 |
When we access that index with && operator, we are using stragety 1 overlap, which corresponding operator oid is 2750.
postgres=# select * from pg_operator where oid = 2750;
-[ RECORD 1 ]+-----------------
oprname | &&
oprnamespace | 11
oprowner | 10
oprkind | b
oprcanmerge | f
oprcanhash | f
oprleft | 2277
oprright | 2277
oprresult | 16
oprcom | 2750
oprnegate | 0
oprcode | arrayoverlap
oprrest | arraycontsel
oprjoin | arraycontjoinsel
The underlying C function to judge arrayoverlap is arrayoverlap in here
Datum
arrayoverlap(PG_FUNCTION_ARGS)
{
AnyArrayType *array1 = PG_GETARG_ANY_ARRAY_P(0);
AnyArrayType *array2 = PG_GETARG_ANY_ARRAY_P(1);
Oid collation = PG_GET_COLLATION();
bool result;
result = array_contain_compare(array1, array2, collation, false,
&fcinfo->flinfo->fn_extra);
/* Avoid leaking memory when handed toasted input. */
AARR_FREE_IF_COPY(array1, 0);
AARR_FREE_IF_COPY(array2, 1);
PG_RETURN_BOOL(result);
}
It actually use array_contain_compare to test whether two array are overlap
static bool
array_contain_compare(AnyArrayType *array1, AnyArrayType *array2, Oid collation,
bool matchall, void **fn_extra)
Line 4177, we see a nested loop to iterate two array, which makes it O(N^2)
for (i = 0; i < nelems1; i++)
{
Datum elt1;
bool isnull1;
/* Get element, checking for NULL */
elt1 = array_iter_next(&it1, &isnull1, i, typlen, typbyval, typalign);
/*
* We assume that the comparison operator is strict, so a NULL can't
* match anything. XXX this diverges from the "NULL=NULL" behavior of
* array_eq, should we act like that?
*/
if (isnull1)
{
if (matchall)
{
result = false;
break;
}
continue;
}
for (j = 0; j < nelems2; j++)